Login or Sign Up

Ask a New Question

A chemist dilutes 144.0 mL of 0.0743 M HCl with 775.0 mL of water. Determine the pH of the diluted solution.

1.86, 1.13, 2.08, 1.93, 12.07

moles HCl = M x L

New concn = moles/new L

Similar Questions

A chemist needs a HCl solution with a molarity of less than 0.400 M for an experiment. To find out if a sample of HCl solution

Top answer: mLHCl x MHCl = mLNaOH x MNaOH Substitute and solve for MHCl and compare with 0.400. Of course you Read more.
An analytical chemist weighs out 0.132 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark

Top answer: First, we need to determine the number of moles of NaOH that reacted with the triprotic acid. We can Read more.
An analytical chemist weighs out 0.225g of an unknown diprotic acid into a 250mL volumetric flask and dilutes to the mark with

Top answer: To calculate the molar mass of the unknown diprotic acid, we first need to determine the number of Read more.
An analytical chemist weighs out 0.291 g of an unknown diprotic acid into a 250 mL volumetric flask and dilutes to the mark with

Top answer: To solve this problem, we need to use the concept of stoichiometry and the relationship between the Read more.
DR.BOB 22 PLS HELPA chemist dissolves 0.099 g of CuSO4 · 5 H2O in water and dilutes the solution to the mark in a 500-mL

Top answer: mols = grams/molar mass = 0.099 g/249.5 = 0.000397 in the first flask so M = mols/L = 0.000397/0.500 Read more.
A chemist wants to make a solution of 3.4 M HCl. There are two solutions of HCL that he can find on the shelf. One has a

Top answer: Technically the chemist can use either; however, the 2.0M would need to be evaporated to arrive at a Read more.
When a chemist dilutes pure acid with another substance, the resulting mixture is no longer pure acid. Consistent with the

Top answer: naturally, that would be 0.40 * 20, right? Read more.
When you complete a acid base titration of NaOH and HCl and how to you find the molarity/concentration of HCl. I used 9 mL of

Top answer: You would do better to post your question instead of parts of it. In general, however, in a Read more.
A chemist dissolves 0.096 g of CuSO4 · 5 H2O in water and dilutes the solution to the mark in a 500-mL volumetric flask. A

Top answer: moles CuSO4.5H20=.096/250 moles transfered: 10.8/.500*.096/250 molarity second solultion: Read more.
A chemist dissolves 0.096 g of CuSO4 · 5 H2O in water and dilutes the solution to the mark in a 500-mL volumetric flask. A

Top answer: I don't think so. Where did you get 43.6 mL? That isn't anywhere in the problem. mols CuSO4.5H2O = Read more.