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A 35.0 ml sample of 0.225 M HBr was titrated with 42.3 ml of KOH. What is the concentration of the KOH?

  • chemistry -

    mLacid x M acid = mL base x M base.

  • chemistry -

    vol x molarity = vol x molarity

    molarity of KOH = 35/42.3 x .225 M = 0.186 M, the first option.

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