You have a 0.0825 M solution of HCl. You expect the pH to be

(H^+) = (HCl) and

pH = -log(H^+)

To determine the expected pH of a 0.0825 M solution of HCl, you can use the equation for the dissociation of HCl in water:

HCl -> H+ + Cl-

Since HCl is a strong acid, it completely dissociates in water, meaning the concentration of H+ ions will be equal to the initial concentration of HCl.

Therefore, the concentration of H+ ions in the solution is also 0.0825 M.

To find the pH of the solution, you can use the equation:

pH = -log[H+]

Let's substitute the concentration of H+ ions into the equation:

pH = -log(0.0825)

Using a calculator, you can find the logarithm and calculate the pH of the solution.

To determine the pH of a solution, you need to use the equation:

pH = -log[H+]

Where [H+] represents the concentration of hydrogen ions in the solution. In this case, the solution is a 0.0825 M (Molar) HCl solution.

Since HCl is a strong acid, it dissociates completely in water, which means that every molecule of HCl will release one hydrogen ion (H+). Therefore, the concentration of hydrogen ions in the solution is equal to the molar concentration of HCl.

So in this case, [H+] = 0.0825 M.

Now, you can plug this concentration value into the pH equation:

pH = -log(0.0825)

Using a calculator, the result is approximately 1.08.

Therefore, you would expect the pH of a 0.0825 M HCl solution to be approximately 1.08.