science
posted by hannah .
Earths mass is 6 x 10^24kg and its radius is 6.38 x 10^6m
(6380 km ). Use the inversesquare law to show that in spaceshuttle territory, 200 km above the earths surface the force of gravity on a shuttle is about 94% of that at the earths surface.

Let the acceleration of gravity at 200 km altitude be g' and the value at sea level be g. Then
g'/g = (6380/6580)^2 = 0.94013
The rounds off to 94%, to the nearest 1%.