NaHCO3+CH3COOH→H2CO3+NaCH3COO
the mass of can changes after reaction, what would be a logical mass?
You need to read, then work on your post. It makes no sense as written.
To determine the logical mass after the reaction, you will need to consider the stoichiometry of the balanced equation and the conservation of mass principle.
The balanced equation for the reaction you provided is:
NaHCO3 + CH3COOH → H2CO3 + NaCH3COO
From the equation, you can determine that one mole of NaHCO3 reacts with one mole of CH3COOH to produce one mole of H2CO3 and one mole of NaCH3COO.
To find the logical mass after the reaction, you should consider the molar masses of the substances involved. The molar mass of NaHCO3 is approximately 84.01 g/mol, and the molar mass of CH3COOH is approximately 60.05 g/mol.
To calculate the logical mass after the reaction, you need to first determine the number of moles of NaHCO3 and CH3COOH used:
Number of moles of NaHCO3 = Mass of NaHCO3 / Molar mass of NaHCO3
Number of moles of CH3COOH = Mass of CH3COOH / Molar mass of CH3COOH
Since the reaction follows a 1:1 stoichiometry, the moles of NaHCO3 used will be equal to the moles of CH3COOH used.
Next, you can calculate the number of moles of H2CO3 and NaCH3COO produced, which will also be equal to the moles of NaHCO3 and CH3COOH reacted.
Finally, to find the logical mass after the reaction, you can use the mass of the products (H2CO3 and NaCH3COO) and subtract the total mass of the reactants (NaHCO3 and CH3COOH) consumed. This will give you the mass change in the can.
Please note that without the specific masses of the reactants and products, it is not possible to provide an exact logical mass after the reaction.