Ethyl alcohol has been added to 190 {\rm mL} of water in a container that has a mass of 140 {\rm g} when empty. The resulting container and liquid mixture has a mass of 450 {\rm g}.

What volume of alcohol was added to the water?

To find the volume of alcohol that was added to the water, we need to calculate the mass of the alcohol and then convert it to volume.

Let's start by finding the mass of alcohol in the mixture:
Mass of the container and liquid mixture = 450 g
Mass of the empty container = 140 g

Mass of the liquid mixture = Mass of the container and liquid mixture - Mass of the empty container
= 450 g - 140 g
= 310 g

Now, we need to find the mass of water in the mixture. Since we know the total volume of water added (190 mL), we can use the density of water to calculate its mass. The density of water is approximately 1 g/mL.

Mass of water = Volume of water Γ— Density of water
= 190 mL Γ— 1 g/mL
= 190 g

Finally, to find the mass of alcohol, we subtract the mass of water from the mass of the liquid mixture:
Mass of alcohol = Mass of liquid mixture - Mass of water
= 310 g - 190 g
= 120 g

Now, to find the volume of alcohol, we use the fact that the density of ethyl alcohol is approximately 0.79 g/mL.

Volume of alcohol = Mass of alcohol / Density of alcohol
= 120 g / 0.79 g/mL
β‰ˆ 151.9 mL

Hence, approximately 151.9 mL of alcohol was added to the water.