# precalc

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Use Sigma Notation to write the sum

[10-(1/10)^2]+[10-(2/10)^2]+[10-(3/10)^2]+[10-(4/10)^2]

• precalc -

Just look at the pattern. The only thing that changes is the denominator.
would it not be ..

4
∑ (10 - i/10)^2
i=1

?

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