Suppose that the following solution is diluted by adding the indicated amount of water. Calculate the new concentration of 225 mL of 3.02 M HCl; 375 mL water added

3.02M x [225 mL/(225+375)] = ?

To calculate the new concentration after diluting a solution, you need to use the equation:

M1V1 = M2V2

where:
M1 = initial concentration of the solution
V1 = initial volume of the solution
M2 = final concentration after dilution
V2 = final volume after dilution

In this case, the initial concentration (M1) is 3.02 M, and the initial volume (V1) is 225 mL. The amount of water added is 375 mL. To find the final concentration (M2), we need to calculate the final volume (V2) after dilution.

V2 = V1 + water added = 225 mL + 375 mL = 600 mL

Now we can substitute the values into the equation:

M1V1 = M2V2
(3.02 M)(225 mL) = M2(600 mL)

Next, rearrange the equation to solve for M2:

M2 = (3.02 M)(225 mL) / (600 mL)

M2 = 1.1335 M

Therefore, the new concentration of the solution after dilution with 375 mL of water is approximately 1.1335 M.