How many moles of hydrogen gas will be produced when the 0.03 g of magnesium reacts with excess hydrochloric acid?
I think it is 1.4 * 10^-3 moles. Im just a grade 11 chem student doing this lab right now LOL.
To determine the number of moles of hydrogen gas produced, you will need to use stoichiometry, which involves balancing the chemical equation and using the molar ratios between the reactants and products.
The balanced chemical equation for the reaction between magnesium and hydrochloric acid is:
Mg + 2HCl -> MgCl2 + H2
From the equation, you can see that 1 mole of magnesium reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas. The molar mass of magnesium (Mg) is 24.31 g/mol.
First, calculate the number of moles of magnesium (Mg) using the molar mass:
Number of moles of Mg = mass of Mg / molar mass of Mg
= 0.03 g / 24.31 g/mol
Next, using the stoichiometric ratio, you can determine the number of moles of hydrogen gas produced:
Number of moles of H2 = Number of moles of Mg x (1 mole of H2 / 1 mole of Mg)
= (0.03 g / 24.31 g/mol) x (1 mol H2 / 1 mol Mg)
Simplify and calculate the result to find the number of moles of hydrogen gas produced.