algebra 1
posted by kit kat .
The difference of two numbers is 5. Three times the larger, decreased by 5 times the smaller is 7. Find the numbers

X = The larger n#.
Y = The smaller #.
Eq2: X  Y = 5.
Eq2: 3X  5Y = 7
Multiply Eq1 by 3:
3X +3Y = 15
3X  5Y = 7
Sum: 2y = 8,
Y = 4.
In Eq1,substitute 4 for Y:
x  4 = 5,
X = 9.
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