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A wheel of mass 0.47 kg and radius 49 cm is spinning with an angular velocity of 24 rad/s. You then push your hand against the edge of the wheel, exerting a force F on the wheel as shown in the figure below. If the wheel comes to a stop after traveling 1/4 of a turn, what is F?

  • physics -

    Torque*Angle = (Kinetic energy lost)

    F*R*(pi/2) = (1/2)*I*wo^2
    = (1/4)*M*R^2*24^2

    Solve for F.

    wo = 24 rad/s
    R = 0.49 m
    M = 0.47 kg

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