The planet Krypton has a mass of

7.1 × 1023 kg and radius of 3.3 × 106 m.
What is the acceleration of an object in free
fall near the surface of Krypton? The gravita-
tional constant is 6.6726 × 10−11 N · m2/kg2.
Answer in units of m/s2

Force of gravity=(Gm1m2)/(r squared)

m1g=(Gm1m2)/(r squared)
g=(Gm2)/(r squared)
m2=Krypton's mass=7.1x10^23 kg
r= Krypton's radius=3.3x10^6m
G=6.6726x10^-11 (N x m^2)/kg^2
Plug in the numbers. You should get
28.265875m/s^2

To calculate the acceleration of an object in free fall near the surface of Krypton, you can use the formula for gravitational acceleration:

acceleration = (G * mass) / radius^2

Given:
Mass of Krypton (m) = 7.1 × 10^23 kg
Radius of Krypton (r) = 3.3 × 10^6 m
Gravitational constant (G) = 6.6726 × 10^-11 N · m^2/kg^2

Substituting the values into the formula:

acceleration = (6.6726 × 10^-11 N · m^2/kg^2 * 7.1 × 10^23 kg) / (3.3 × 10^6 m)^2

Simplifying and calculating:

acceleration ≈ 13.7 m/s^2

Therefore, the acceleration of an object in free fall near the surface of Krypton is approximately 13.7 m/s^2.

To find the acceleration of an object in free fall near the surface of Krypton, we can use Newton's law of universal gravitation. The formula for gravitational acceleration near the surface of a planet is given by:

a = (G * M) / r^2

Where:
a is the acceleration
G is the gravitational constant (6.6726 × 10−11 N · m2/kg2)
M is the mass of the planet (7.1 × 10^23 kg)
r is the radius of the planet (3.3 × 10^6 m)

Plugging in the given values into the formula:

a = (6.6726 × 10−11 N · m2/kg2 * 7.1 × 10^23 kg) / (3.3 × 10^6 m)^2

Simplifying:

a = (4.717246 × 10^13 N · m/kg) / (1.089 × 10^13 m^2)

Dividing the numerator by the denominator:

a = 4.3314 m/s^2

Therefore, the acceleration of an object in free fall near the surface of Krypton is approximately 4.3314 m/s^2.