What mass of steam is required to release 4.36 × 105 kJ of heat energy on condensation? answer in unit of g.
4.36E8 J = mass x heat vaporization/condensation
To calculate the mass of steam required to release a certain amount of heat energy on condensation, we need to use the concept of the specific heat capacity.
The specific heat capacity of water is the amount of heat energy required to raise the temperature of one gram of water by one degree Celsius. For water, this value is approximately 4.18 J/g°C.
First, let's convert the given value of heat energy from kJ to J:
4.36 × 10^5 kJ = 4.36 × 10^8 J
Now, let's use the equation:
Q = m * c * ΔT
where Q is the heat energy released, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
In this case, the change in temperature is the boiling point of water (100°C) since steam condenses back into water at this temperature.
Rearranging the equation to solve for the mass of the steam:
m = Q / (c * ΔT)
m = (4.36 × 10^8 J) / (4.18 J/g°C * 100°C)
m = 1.04 × 10^6 g
Therefore, the mass of steam required to release 4.36 × 10^5 kJ of heat energy on condensation is 1.04 × 10^6 grams.
To determine the mass of steam required to release a certain amount of heat energy on condensation, we need to use the equation:
Q = m * ΔH
Where Q is the heat energy released, m is the mass of the substance, and ΔH is the heat of vaporization/condensation.
In this case, we are given:
Q = 4.36 × 10^5 kJ
We need to find the mass, so let's rearrange the equation to solve for mass:
m = Q / ΔH
The heat of vaporization/condensation for water is approximately 40.7 kJ/g (at 100°C). So, we can substitute this value into the equation:
m = 4.36 × 10^5 kJ / 40.7 kJ/g
Calculating:
m = 10713.25 g
Therefore, the mass of steam required to release 4.36 × 10^5 kJ of heat energy on condensation is approximately 10713.25 g.