Using electron bookkeeping draw a Lewis dot diagram for NF2H and N2H2 determine how many electrons each atom should be assigned.
Thanks Guys I really appreciate it, my assignment is due tonight and the test is tomorrow, could you explain it,thanks
These are almost impossible to draw on this board. You have 26 electrons.
Draw N on a sheet of paper, place F, F, and H on each of three sides. Place two electrons between each to show the covalent bond. Place six more electrons around each F and place the last two electrons on the fourth side of N so it will be an unshared pair.
H:N::N:H with a lone pair above each N.
You post sounds as if you want the formal charge. The formal charge on all of the atoms in each structure is zero.
Thanks DR Bob
: : :
: F : N : F :
: : :
H
DR Bob this is what I drew, I know its not lined up but could you explain the method of electron booking for me.
Thanks again
To draw a Lewis dot diagram for a molecule, you need to determine the number of valence electrons for each atom in the molecule.
For NF2H:
- In the periodic table, nitrogen (N) is located in group 15, so it has 5 valence electrons.
- Fluorine (F) is in group 17, which means it has 7 valence electrons each. There are two fluorine atoms, so a total of 2 x 7 = 14 electrons.
- Hydrogen (H) is in group 1 and has 1 valence electron. There is one hydrogen atom, so 1 valence electron in total.
To calculate the total number of valence electrons in NF2H, add up the valence electrons for each atom:
5 (N) + 14 (2 x F) + 1 (H) = 20 valence electrons.
Next, we will position the atoms. Nitrogen (N) will be the central atom since it is less electronegative than fluorine (F) and hydrogen (H). The hydrogen atoms (H) will be placed around the nitrogen (N) atom, and the fluorine atoms (F) will be placed on the outer sides.
The Lewis dot structure for NF2H is as follows:
F
|
H-N-F
|
F
Now, let's move onto N2H2:
- Nitrogen (N) has 5 valence electrons.
- Hydrogen (H) has 1 valence electron. There are two hydrogen atoms, so a total of 2 x 1 = 2 electrons.
To calculate the total number of valence electrons in N2H2, add up the valence electrons for each atom:
5 (2 x N) + 2 (2 x H) = 12 valence electrons.
Since both nitrogen atoms need to be placed in the center for N2H2, the Lewis dot structure looks like this:
H-N=N-H
In this structure, the two nitrogen atoms share a triple bond (three shared pairs of electrons) represented by the three lines (=). Each nitrogen atom also has a lone pair of electrons, and each hydrogen atom is bonded to a nitrogen atom.
I hope this explanation helps you draw the Lewis dot diagrams for NF2H and N2H2. Good luck with your assignment and test!