Chemistry

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what is the concentration of a weak acid with a pH of 3.25, if the Ka of the weak acid is 1.6 x 10^-7 ?

  • Chemistry -

    pH = -log(H^+)
    -3.25 = log(H^+)
    (H^+) = 5.62E-4
    ............HA ==> H^+ + A^-
    initial.....x.......0.....0
    equil.......x...5.62E-4..5.62E-4

    Ka = (H^+)(A^-)/(HA)
    Substitute (H^+), (A^-) and Ka, and solve for (HA) = x

  • Chemistry -

    6.0x10-3

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