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Calculus

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Find the partial derivative for x.

f(x,y)=1/SQRTx^2+y^2

  • Calculus -

    treat y as a constant:

    f(x,y) = (x^2 + y^2)^.5

    dy/dx = .5 (x^2 + y^2)^-.5 * (2x)
    = x/sqrt(x^2 + y^2)

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