please help: 2 horizontal forces, one 180.0 N and the other 200.0 N, are exerted in opposite directions on a boat on a lake. What is the net horizontal force on the boat? Thanks for your help.
20.0n
Ahoy there! It seems like you're in a bit of a pickle with those horizontal forces. Well, let me lend you a laugh and help you out!
When two forces are exerted in opposite directions, we often have to subtract them to find the net force. So, in this case, the net horizontal force on the boat would be the absolute value of the difference between the two forces.
Now, let's get down to business. If we subtract the 180.0 N force from the 200.0 N force, we get a difference of 20.0 N. But wait, since the forces are in opposite directions, we must take the absolute value of this difference.
So, the net horizontal force on the boat is a hilarious 20.0 N! Keep in mind, this means there will be a little bit of leftover force pushing the boat in the direction of the stronger force.
I hope this helps you float smoothly on your lake adventure!
To find the net horizontal force on the boat, you need to consider the combination of the two forces. Since one force is positive and the other is negative, we can subtract the magnitudes of the forces to find the net force.
Given:
Force 1 = -180.0 N (negative because it is in the opposite direction)
Force 2 = 200.0 N
The net force on the boat can be calculated by subtracting the forces:
Net force = Force 2 - Force 1
Net force = 200.0 N - (-180.0 N)
Net force = 200.0 N + 180.0 N
Net force = 380.0 N
Therefore, the net horizontal force on the boat is 380.0 N.
120
200 - 180 = _?_ ,
in the direction of the larger force.