Please help. Thanks! A car/truck with an initial displacement of 10.0 m and an initial velocity of 16.0 m/s accelerates at an average rate of 0.50 m/s2 for 4.0 s. What is the vehicle's displacement after 4.0 s?
10 + Vo*t + (a/2)*t^2
Vo = 16 m/s
a = 0.50 m/s^2
t = 4 seconds
10 + (16*4) + (0.5*0.5*4^2) = ?
fera
To find the vehicle's displacement after 4.0 seconds, you can use the equation of motion:
displacement = initial displacement + (initial velocity * time) + (0.5 * acceleration * time^2)
Given:
Initial displacement (s0) = 10.0 m
Initial velocity (v0) = 16.0 m/s
Acceleration (a) = 0.50 m/s^2
Time (t) = 4.0 s
Now, let's plug in the values into the equation:
displacement = 10.0 m + (16.0 m/s * 4.0 s) + (0.5 * 0.50 m/s^2 * (4.0 s)^2)
Calculating the above expression step by step:
displacement = 10.0 m + (16.0 m/s * 4.0 s) + (0.5 * 0.50 m/s^2 * 16.0 s^2)
displacement = 10.0 m + (64.0 m) + (0.5 * 0.50 m/s^2 * 256.0 s^2)
displacement = 10.0 m + 64.0 m + 64.0 m
displacement = 138.0 m
Therefore, the vehicle's displacement after 4.0 seconds is 138.0 meters.