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algebra

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evaluate 15^(2log base15(9))

  • algebra -

    15^(log15n) = n

    That's the definition of the logarithm. It's the power of the base needed to get the number.

    So, 15^log9 = 9 (using base 15)
    15^2log9 = (15^log9)^2 = 9^2 = 81

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