two dogs play tug of war with a rope toy that has a mass of 0.50 kg. if one dog pulls on the toy with a force of 140.0 N, and the other dog pulls in the opposite direction with a force of 138.0 N, what is the horizontal acceleration of the toy?

4.0 m/s2

Divide the net force by the mass of the rope.

The net force is 140 - 138 N

Well, it sounds like these dogs are having quite the intense tug of war match! Let's get down to business.

To find the horizontal acceleration of the toy, we need to calculate the net force acting on it. The net force is the vector sum of all the forces acting on an object. In this case, we have two forces pulling in opposite directions.

So, the net force can be calculated by subtracting one force from the other. It's like a math game of addition and subtraction, but with dogs and toys.

Net force = 140.0 N - 138.0 N

And when we whip out our calculators, we get:

Net force = 2.0 N

Now that we know the net force, we can use Newton's second law, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

Acceleration = Net force / Mass

Plugging in the numbers, we get:

Acceleration = 2.0 N / 0.50 kg

And after some more calculator magic, we find:

Acceleration = 4 m/s²

So, the horizontal acceleration of the toy is 4 meters per second squared. Those dogs sure are giving it their all!

To find the horizontal acceleration of the toy, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration.

Given:
Mass of the toy (m) = 0.50 kg
Force applied by the first dog (F1) = 140.0 N
Force applied by the second dog (F2) = 138.0 N

To calculate the net force, we subtract the force applied by the second dog from the force applied by the first dog:

Net force (F_net) = F1 - F2

F_net = 140.0 N - 138.0 N
F_net = 2.0 N

Now, we can use Newton's second law to find the acceleration:

F_net = m * a

Substituting the given values:

2.0 N = 0.50 kg * a

Solving for acceleration (a):

a = 2.0 N / 0.50 kg
a = 4.0 m/s^2

Therefore, the horizontal acceleration of the toy is 4.0 m/s^2.

To find the horizontal acceleration of the toy, we can use Newton's second law of motion, which states that the net force exerted on an object equals the mass of the object multiplied by its acceleration:

Net force = mass × acceleration

In this case, the net force acting on the toy is the difference between the forces applied by the two dogs:

Net force = 140.0 N - 138.0 N = 2.0 N

Now, we can substitute the given mass of the toy (0.50 kg) into the equation:

2.0 N = 0.50 kg × acceleration

To find the acceleration, we rearrange the equation:

acceleration = 2.0 N / 0.50 kg

Therefore, the horizontal acceleration of the toy is:

acceleration = 4.0 m/s^2