math divisibility
posted by marko .
i need to write the missing digit to make each number divisible by 3
1,843,#89
i got the missing number as : 3
s/b 1,843,389 is that right?
#2 i need to write the missing digit to make each number divisible by 8
2,4#2 i cant figure that out
i got : 2,422? is that right?
#3 i need to write the missing digit to make each number divisible by 8
1,325,#84
i got: 4
so should be: 1, 1,325,484 is that right?

1. A number is divisible by 3 if the sum of its digits is divisible by 3
so far we have a sum of 33, which is divisible by 3
so the missing # could be 0, 3, 6, or 9
2. The fist 2 digits divide by 8, so #2 must divide by 8
only possible case is 32 or 72
3. Any number is divisible by 8 if its last 3 digits evenly divide by 8
184 does, so does 384, 584, 784, and 984
so 1325184, 1325384, etc 
Didn't get a answer