Chemistry

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a coffee cup calorimeter normally consists of two nested styrofoam cups with a lid. a coffee cup calorimeter of this type contains 125.0 g of water at 20.00 degrees C. A 120.0 g sample of copper metal is heated to 98.0 degrees C by putting it into a beaker of hot water. The copper is then put into the calorimeter and the final temperature of the water and copper is 25.80 degree C

calculate the energy change of the copper metal?

  • Chemistry -

    heat lost by Cu = heat gained by H2O.
    q = heat gained by water = mass H2O x specific heat H2O x (Tfinal-Tinitial).

    OR, heat lost by Cu is
    mass Cu x specific heat Cu x (Tfinal-Tinitial)

  • Chemistry -

    still don't get it

  • Chemistry -

    q= 20.00 C =125.0g x 98.0 C x 25.80 C -20.00??

  • Chemistry -

    Well, it's a funny question, at least in the wording. Questions of this type USUALLY ask for the final T or give the final T and ask for the initial T. Still others give both final T and initial T and ask for specific heat or the mass of the metal or the mass of water. In this case, however, the problem give mass, I assume they intend you to look up the specific heats (of Cu or H2O) and it gives final T and initial T. It asks for energy (which I translate as heat)
    "Still don't get it" isn't very helpful. you need to tell us what you problem is. My first response gives you my rationale and I see no point in repeating what I wrote above. The numbers are not what you have placed in what appears to be a random order.
    q = heat lost by copper = energy lost by copper = mass copper x specific heat copper x (Tfinal-Tinitial).

    mass copper = 120.0 g
    specific heat copper--That isn't given in the problem. I assume you are look it up in tables in your text and/or notes.
    Tfinal = 25.80 C
    Tinitial = 98.0
    Solve for q.

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