ZnCl2(aq)+Na2CO3(s)--> ZnCO3(s)+NaCl (aq) Balance the chemical equation and state solid, liq, gas, aq properly to each compound
Ok I have it balanced by 2 NaCl in the second part of the equation But now what is the total ionic and net ionic equations?
The molecular equation is converted to the total ionic equation with the following rules:
1. ionic and soluble compounds written as ions.
2. insoluble compounds written as molecules and solids. Here is a simplified list of the solubility rules.
http://www.files.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html
3. Gases are written as molecules.
4. Slightly ionized materials are written as molecules.
Then the total ionic equation is converted to the net ionic equation by canceling ions common to both sides of the total net ionic equation.
Post your work if you get stuck.
To write the total ionic equation, we need to dissociate all the soluble compounds into their respective ions. In this case, ZnCl2 and NaCl are both soluble compounds.
The balanced chemical equation is:
ZnCl2(aq) + Na2CO3(s) → ZnCO3(s) + 2NaCl(aq)
Now, let's write the total ionic equation:
Step 1: Write the balanced molecular equation.
ZnCl2(aq) + Na2CO3(s) → ZnCO3(s) + 2NaCl(aq)
Step 2: Dissociate any soluble ionic compounds.
ZnCl2(aq) → Zn^2+(aq) + 2Cl^-(aq)
Na2CO3(s) → 2Na^+(aq) + CO3^2-(aq)
ZnCO3(s) remains unchanged as it is already a solid.
2NaCl(aq) → 2Na^+(aq) + 2Cl^-(aq)
Now, let's write the total ionic equation using the dissociated ions:
Zn^2+(aq) + 2Cl^-(aq) + 2Na^+(aq) + CO3^2-(aq) → ZnCO3(s) + 2Na^+(aq) + 2Cl^-(aq)
To write the net ionic equation, we need to remove the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the reaction.
In this case, the spectator ions are 2Na^+(aq) and 2Cl^-(aq). They appear on both sides and do not undergo any change.
Thus, the net ionic equation is:
Zn^2+(aq) + CO3^2-(aq) → ZnCO3(s)
In summary, the total ionic equation is:
Zn^2+(aq) + 2Cl^-(aq) + 2Na^+(aq) + CO3^2-(aq) → ZnCO3(s) + 2Na^+(aq) + 2Cl^-(aq)
And the net ionic equation is:
Zn^2+(aq) + CO3^2-(aq) → ZnCO3(s)