slope=2/5,{10, 3} is on the line
find the y-intercept: y= mx + b
___ = {---} ____ +b
You know the equation is
y = mx + b
So, plug in the data they gave you:
3 = 2/5 (10) + b
3 = 4+b
b = -1
So, the equation is
y = 2/5 x - 1
Since this is called the slope-intercept form of a line, take a stab at the y-intercept. (Hint: that is the point on the graph where x=0)
To find the y-intercept, we can use the given point that is on the line, which is (10, 3).
Let's substitute the slope and the point into the equation y = mx + b:
3 = (2/5)(10) + b
Now we can solve for b:
3 = 20/5 + b
3 = 4 + b
b = 3 - 4
b = -1
Therefore, the y-intercept is -1.
To find the y-intercept (b) of the line, we need to use the given slope (m) and any point (x, y) that lies on the line.
Given:
Slope (m) = 2/5
Point (x, y) = (10, 3)
The general equation for a line is y = mx + b.
Substituting the values we have:
3 = (2/5) * 10 + b
Now we can solve for b:
Multiply (2/5) by 10: (2/5) * 10 = (2 * 10) / 5 = 20/5 = 4
So, the equation becomes:
3 = 4 + b
To isolate b, we subtract 4 from both sides of the equation:
3 - 4 = b
-1 = b
Therefore, the y-intercept of the line is -1, and the equation of the line becomes:
y = (2/5)x - 1