posted by Marni .
cos t=.7, tan t<0. find the values of the other 5 trigonometric functions.
draw the triangle: adjacent+.7, hypo, 1.0, opposite -.51
Tant=.51/.70, sint=-.51/1.0, and so on.
are you meant t is negative?
cost >0 and tant< 0 , then t is in IV
if cos t = .7 = 7/10, then my triangle is 7 - √51 - 10
sint = -√51/10 , csc t = -10/√51
cos t = 7/10, sec t = 10/7
tan t = -V51/7 , cot t = -7/√51