A block of mass 20kg resting on a horizontal force 50N.If the coefficient of friction between the table and the block is 0.45,calculate the acceleration with which it moves

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You omitted some words in your question. How can you rest on a force?

This is a physics question. The math is trivial.

If 50 N is pushing the block, and the static friction coefficient is 0.45, a friction force of up to 0.45 M g = 88 N will tend to keep it in place. 50 N is not enough to move it.

In this case, the block will not move at all.

To calculate the acceleration with which the block moves, we need to consider the forces acting on the block.

In this case, we have the following forces:

1. Force pushing the block: This is the horizontal force applied to the block, which is given as 50N.
2. Weight of the block: This is the force exerted by gravity on the block and can be calculated using the equation: Weight = mass * acceleration due to gravity. Since the block is on a horizontal surface, we can ignore the vertical component of the weight.
Weight = 20kg * 9.8 m/s^2 = 196 N
3. Frictional force: The frictional force is given by the equation: Frictional force = coefficient of friction * normal force. The normal force is equal to the weight of the block, so in this case:
Frictional force = 0.45 * 196 N = 88.2 N

To find the net force acting on the block, we subtract the frictional force from the force pushing the block:
Net force = Force pushing the block - Frictional force
Net force = 50N - 88.2N = -38.2 N

Since force is equal to mass times acceleration (F = m * a), we can rearrange this equation to solve for acceleration:
Acceleration = Net force / mass
Acceleration = -38.2 N / 20 kg
Acceleration = -1.91 m/s^2

Therefore, the block will have an acceleration of -1.91 m/s^2. The negative sign indicates that the block is moving in the opposite direction of the applied force, i.e., it is slowing down or resisting the force.