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A 64.2-kg skier coasts up a snow-covered hill that makes an angle of 23.8° with the horizontal. The initial speed of the skier is 7.18 m/s. After coasting 1.96 m up the slope, the skier has a speed of 3.13 m/s. Calculate the work done by the kinetic frictional force that acts on the skis.

  • physics -

    when up vertically 1.96 sin 23.8
    call that h = 1.96 sin 23.8
    gain in potential energy = m g h

    inital Ke = (1/2) m (7.18)^2 = initial total Energy
    final total energy = (1/2)m(3.13)^2+m g h

    loss to friction = inital total - final total

    = (1/2)m(7.18^2-3.13^2) -mgh

  • physics -

    -842.72 J

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