advanced algebra
posted by kmoore .
How do you factor
9(b to the 4th power)  200

9b^4  200
= (3b^2  √200)(3b^2 + √200)
= (√3b  √√200)(√3b + √√200)(3b^2 + √200)
where √√200 means the 4th root.
Not sure how far you want to go with this. We could also factor using complex numbers:
= (√3b  √√200)(√3b + √√200)(√3b  i√√200)(√3b + i√√200)
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