an averaga-sided female spider and a large spider can lay a total of 2100 eggs at one time. the large spider lays 20 times the number of eggs as the average sized spider. how many eggs does the average side spider lay?
As+Ls=2100
Ls=large spider as=average sized spider
Ls=20As
so
as+20as=2100
21as=2100
as=100
The average sized spider lays 100 eggs at one time
let the no. of eggs laid by average side spider=x
given, 20x= 2100
divide both sides by 20
20x/20 = 2100/20
x =105
. .
. the no. of eggs laid by an average side spider = 105 eggs
To find out how many eggs the average-sized spider lays, we need to set up an equation based on the information given.
Let's assume the number of eggs the average-sized spider lays is represented by 'x'. According to the problem, the large spider lays 20 times the number of eggs as the average-sized spider. So, the number of eggs the large spider lays would be 20x.
Now, we can set up an equation to express the total sum of eggs:
x + 20x = 2100
Combining like terms, we have:
21x = 2100
To solve for x, we divide both sides of the equation by 21:
x = 2100 ÷ 21
x = 100
Therefore, the average-sized spider lays 100 eggs.