how long does a car with an acceleration of 2.0 m/s^2 take to go from 10m/s to 30m/s?and show the solution how do you get the answer.
t = (Vf - Vo) / a,
t = (30 - 10) / 2 = 10s.
To calculate the time it takes for a car with an acceleration of 2.0 m/s^2 to go from 10 m/s to 30 m/s, we can use the formula:
v = u + at,
where:
v is the final velocity (30 m/s),
u is the initial velocity (10 m/s),
a is the acceleration (2.0 m/s^2), and
t is the time (which we need to find).
To find the time, we need to rearrange the formula:
t = (v - u) / a.
Plugging in the given values:
t = (30 m/s - 10 m/s) / 2.0 m/s^2.
Simplifying the equation:
t = 20 m/s / 2.0 m/s^2.
t = 10 s.
Therefore, it takes the car 10 seconds to go from 10 m/s to 30 m/s with an acceleration of 2.0 m/s^2.