a pitches takes 0.10 seconds to throw a baseball, which leaves his hand at a velocity of 30m/s. the balls acceleration is?

acceleration = (final velocity minus initial velocity)/time taken.

the formula is based on newton's 2nd law, which states that the rate of change of momentum of an object is directly proportional to the resultant force acting on it.

F = m(v-u)/t
ma = m(v-u)/t

hence, a=(v-u)/t

a = (30-0)/0.10

To determine the acceleration of the baseball, we can use the equation for acceleration:

acceleration = (final velocity - initial velocity) / time.

In this case, the initial velocity (u) is 0 (as the ball starts from rest) and the final velocity (v) is 30 m/s. The time (t) is given as 0.10 seconds.

Using the equation:
acceleration = (30 m/s - 0 m/s) / 0.10 s = 300 m/s^2.

Therefore, the acceleration of the baseball is 300 m/s^2.