6,11,16,21,....Algebraic expression______
12th term-
30th term-
I can't understand anything on this app
To find the algebraic expression for the given series, we first need to identify the pattern. Looking at the given sequence, it appears that each term is obtained by adding 5 to the previous term. Therefore, the common difference between consecutive terms is 5.
To find the algebraic expression, we can use the formula for arithmetic sequences:
a_n = a_1 + (n - 1)d
Here, a_n represents the nth term, a_1 is the first term, and d is the common difference. In this case, a_1 = 6 and d = 5.
1. To find the 12th term (a_12):
a_12 = 6 + (12 - 1) * 5
= 6 + 11 * 5
= 6 + 55
= 61
Therefore, the 12th term is 61.
2. To find the 30th term (a_30):
a_30 = 6 + (30 - 1) * 5
= 6 + 29 * 5
= 6 + 145
= 151
Therefore, the 30th term is 151.
The algebraic expression for this sequence is:
a_n = 6 + (n - 1) * 5
So, by plugging in the desired value of n, we can find any term in the given series.
6,11,16,21,....Algebraic expression______
12th term-
30th term-
Plz help me plzzz
On a day teacher wrote a sequence in the blackbord .
1, 6, 11, 16, 21, 26, ……
The teacher described this sequence as "it is the
sequence is a, a+d, a+2d, ...
nth term is Tn = a + (n-1)d
So, find d. It's obviously 5. First term a=6
Thus, T12 = 6 + 11*5 = 61
T30 = 6 + 29*5 = 151