# Algebra II

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If both masses are increased by 60% and the distance between them is halved, by what percent will the force of attraction increase?

• Algebra II -

just plug in the new values:

F = GMm/d^2

new force

F' = G(1.6m)(1.6M)/(d/2)^2
= GmM/d^2 * 1.6^2 * 2^2
= 10.24F

I assume you can convert that to a percentage

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