What is molarity of solution made by combining 10.0g of NaOH with enough water to reach a total volume of 2.00L?
moles = grams/molar mass
Then M = moles/L soln.
I went through the equation three times. I got 0.125 M NaOH. Is this correct? Thank you
To find the molarity of a solution, you need to know the number of moles of the solute (in this case, NaOH) and the volume of the solution.
First, let's determine the number of moles of NaOH. To do this, we'll use the formula:
moles = mass (g) / molar mass (g/mol)
The molar mass of NaOH is the sum of the atomic masses of sodium (Na), oxygen (O), and hydrogen (H):
molar mass of NaOH = (atomic mass of Na) + (atomic mass of O) + (atomic mass of H)
= (22.99 g/mol) + (16.00 g/mol) + (1.01 g/mol)
= 40.00 g/mol
Now, we can calculate the number of moles of NaOH:
moles = 10.0 g / 40.00 g/mol
= 0.25 mol
Next, we need to find the volume of the solution. In this case, the volume is given as 2.00 L.
Finally, we can calculate the molarity of the solution using the formula:
molarity = moles / volume
molarity = 0.25 mol / 2.00 L
molarity = 0.125 mol/L
Therefore, the molarity of the NaOH solution is 0.125 mol/L.