posted by Dewa .
At 40 c,the value of Kw is 2.92
10-14.calculate the [H+] and [OH-] of pure water at 40 c.
This question has been answered before.
"the value of Kw is 2.92
10-14" ?? units are missing
Given that [H+][OH-]=Kw and that
[H+] = [OH-] for pure water
[H+][OH-]=[H+][H+]=2.92 x 10^-14
[H+]^2= 2.92 x 10^-14
[H+] = sqrt(2.92 x 10^-14)
but this is missing the units.