# College Algebra..LOG

posted by .

log4(little four) (40 - 3x) = 0
now i need to solve for x...

• College Algebra..LOG -

log 1 = 0 to any base

so,

40-3x = 1
x = 13

## Similar Questions

1. ### Algebra II

Solve, round to four decimal places if necessary: log4(x-9)=2 Answer: x-9=4^2 x-9=16 x=11 log4(z)+log4(z-3)=1 Answer: z+z-3=1 2z=4 z=2 Thanks for checking my work.
2. ### Logarithms

Solve log4 x + log4(x-2)=log4(15) I know how do the example in my book but I don't know what I'm doing wrong here. log4 x + log4(x-2)=log4(15) log4 [x + log4(x-2)]=log4(15) (x^2 + x)=4 x^2 + x-4=0
3. ### Algebra 2

Simplify: 1. 2log10^5+log10^4 2. 2log3^6-log3^4 3. log4^40-log4^5 4. log4^3-log4^48 I need to see all of the steps. Thanks

solve for x: log4 X - log4 2 = 2 log(2x) = 2 Now what do I do?
5. ### Math

solve for x: log4 X - log4 2 = 2 log(2x) = 2 Now what do I do?
6. ### Algebra II

ok now this is an algebra 2 problem... I have goten far down to hear e^(ix) = (4i +/- 3)/5 now how do I solve for x I feel really stupid now as this is algebra 2... can't use natural log right or the common log as ln( e^(ix) ) does …
7. ### college algebra... LOG

log4(little 4) 8 how do i write this in y=?
8. ### College Algebra..LOG

log4(little four) (40 - 3x) = 0 now i need to solve for x...
9. ### precalc

I don't understand how to do these w/o calc. I tried to write it in a way that will make someone understand how to read it. Hope I typed it clear enough.Thanks so much for the help anyone! How to find the exact value of logarithm: …
10. ### Algebra 2

Can someone explain how to figure out these types of problems?

More Similar Questions