What is the molarity of the hydrochloric acid solution used if 25mL of it reacted with excess calcium carbonate to produce 5.3g of calcium chloride?
CaCo3(s) + 2HCl(aq)---> CaCl2(aq) + CO2(g) + H2O(l)
I am really confused on even what this question is asking..any help would be greatly appreciated.
Use stoichiometry to back calculate from 5.3 g CaCl2 to see the moles HCl used (you could go the long way and calculate moles CaCO3 used then convert to HCl but that step isn't necessary).
moles CaCl2 = grams/molar mass = 5.3/about 111 = about 0.048 (but you need to do it again more accurately).
Then convert moles CaCl2 to moles HCl using the coefficients in the balanced equation. 0.048 moles CaCl2 x (2 moles HCl/1 mole CaCl2) = 0.048 x (2/1) = about 0.096 mols HCl.
Then the definition of molarity is M = moles/L; therefore, M HCl = moles HCl/L HCl. You have moles from above, L HCl is given in the problem (25 mL = 0.025L), solve for M.
To determine the molarity of the hydrochloric acid solution, you need to use the given information about the volume of acid used and the amount of product produced.
Step 1: Determine the moles of calcium chloride produced.
You are given that 5.3 g of calcium chloride (CaCl2) was produced. To convert this mass into moles, you need to use the molar mass of calcium chloride.
The molar mass of CaCl2 can be calculated as follows:
- The atomic mass of calcium (Ca) is 40.08 g/mol
- The atomic mass of chlorine (Cl) is 35.45 g/mol
So the molar mass of CaCl2 is (40.08 g/mol) + 2*(35.45 g/mol) = 110.98 g/mol.
To calculate the moles of CaCl2 produced, divide the given mass by the molar mass:
Moles of CaCl2 = 5.3 g / 110.98 g/mol = 0.0477 mol
Step 2: Use stoichiometry to determine moles of HCl used.
From the balanced chemical equation, you can see that the stoichiometric ratio between calcium chloride (CaCl2) and hydrochloric acid (HCl) is 1:2.
Since the moles of CaCl2 produced is 0.0477 mol, the moles of HCl used will be twice that amount:
Moles of HCl = 2 * 0.0477 mol = 0.0954 mol
Step 3: Calculate the molarity of the hydrochloric acid solution.
Molarity (M) is defined as moles of solute per liter of solution. In this case, the solute is HCl, and the volume of the solution is given as 25 mL (0.025 L).
Molarity of HCl = Moles of HCl / Volume of HCl solution
Molarity of HCl = 0.0954 mol / 0.025 L = 3.816 M
Therefore, the molarity of the hydrochloric acid solution used is 3.816 M.
To determine the molarity of the hydrochloric acid (HCl) solution, you need to use the given information about the reaction and stoichiometry.
First, let's understand the question. The question is asking for the molarity of the hydrochloric acid solution, which is a measure of the concentration of the acid. Molarity is defined as the amount of solute (in moles) dissolved in a given volume of solution (in liters).
The equation provided shows the balanced chemical equation for the reaction between calcium carbonate (CaCO3) and hydrochloric acid (HCl), which produces calcium chloride (CaCl2), carbon dioxide (CO2), and water (H2O).
To find the molarity of the hydrochloric acid, we need to follow these steps:
Step 1: Calculate the number of moles of calcium chloride (CaCl2) produced.
Given that 5.3g of calcium chloride is produced, we need to convert this mass to moles. The molar mass of CaCl2 is calculated as follows:
Ca = 40.08 g/mol
Cl = 2 * 35.45 g/mol = 70.90 g/mol
Molar mass of CaCl2 = 40.08 + 70.90 = 111.98 g/mol
To find the number of moles, we use the formula:
moles = mass / molar mass
moles of CaCl2 = 5.3 g / 111.98 g/mol
Step 2: Calculate the number of moles of hydrochloric acid (HCl) used.
According to the balanced chemical equation, the reaction between CaCO3 and HCl is 1:2, which means that 1 mole of CaCO3 reacts with 2 moles of HCl.
Therefore, the number of moles of HCl can be calculated as:
moles of HCl = 2 * moles of CaCl2
Step 3: Calculate the volume of the hydrochloric acid (HCl) solution.
Given that 25 mL of HCl solution was used, we need to convert this volume to liters:
volume (L) = 25 mL / 1000 mL/L
Step 4: Calculate the molarity (M) of the hydrochloric acid (HCl) solution.
Molarity is defined as the number of moles of solute divided by the volume of the solution in liters:
Molarity (M) = moles of HCl / volume (L)
By plugging in the values from the previous steps, you can calculate the molarity of the hydrochloric acid solution.