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a person throws a ball upward into the air with an initial velocity of 15 m/s calculate
a)how high it goes?
b)how long the ball is in the air before it comes back ?
c)how much time it takes for the ball to reach the maximum height?

  • physics -

    h = 15t - 4.9t^2 = 4.9t(3.06-t)

    (c) max height is reached at t = 15/9.8

    (b) h=0 when t=0 or 3.06

    (a) calculate h using (a)

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