log4(little 4) 8
how do i write this in y=?
Use the laws of logarithms,
log ab = log a+log b
logaa = 1, and
loga sqrt(b)=(1/2)loga b
log 8
= log44*2
=log44+log42
=1+loga2
=1+(1/2)log42
=1+(1/2)(1)
=3/2
Use the laws of logarithms,
log ab = log a+log b
logaa = 1, and
loga sqrt(b)=(1/2)loga b
log 8
= log44*2
=log44+log42
=1+log42
=1+(1/2)log44
=1+(1/2)(1)
=3/2
To write log4(8) in terms of y, you can use the change of base formula. The change of base formula states that for any base b, log base b of x is equal to log base c of x divided by log base c of b, where c is any positive number other than 1. In this case, we want to express log4(8) in terms of y. Since y is not a base we commonly use in logarithms, we can choose a base c that is equal to y.
Therefore, the expression log4(8) can be written as log base c of 8 divided by log base c of 4. In other words:
log4(8) = logc(8) / logc(4)
This is the representation of log4(8) in terms of y.