algebra
posted by Zephine
The present ages in years of four cousins are consecutive multiples of 3. Five years ago the sum of their ages was 46. What is their ages now?

Steve
if their ages are a,b,c,d, then
a+b+c+d = 3n + 3n+3 + 3n+6 + 3n+9 = 12n + 18
(a5)+(b5)+(c5)+(d5) = 46
a+b+c+d = 66
so, 12n+18 = 66
n=4
so, the ages are 12,15,18,21
5 years ago, they were 7,10,13,16 and added up to 46
Respond to this Question
Similar Questions

Math
The sum of the ages of a woman and her daughter is 46years.In 4 years, the ratio of their ages will be 7:2. Find their present ages. 
Math
The sum of the ages of a woman and her daughter is 46years.In 4 years, the ratio of their ages will be 7:2. Find their present ages. 
Algebra
Zandile is 4 years older than Thoko.Four years ago the product of their ages was 165.find their present ages 
Math
The sum of ages of two sisters are 19 years.in five years time the product of their ages will be 208.what are their ages? 
math
A man is five times older than his son. Four years ago, the product of their ages was 448. Find their present ages. (5x X x)  4 = 448 x = 9.507 
math
A man is five times older than his son. Four years ago, the product of their ages was 448. Find their present ages. (5x X x)  4 = 448 x = 9.507 
math
Richard is 6 years older than Lisa, and in 5 years the sum of their ages will be twice as much as the sum of their ages 4 years ago. Find their present ages. 
math
The sum of ages of Sam ang thomas is 27 years. Seven years ago, Toma's was three years more than one fourth as old as Sam. Find their present ages 
math
Richard is 6 years older than Lisa, and in 5 years the sum of their ages will be twice as much as the sum of their ages 4 years ago. Find their present ages. 
Maths
The ages of jaso and janam are in the ratio 7:9 four years from now the ratio of their ages will be 4:5 find their present ages