An ice hut used for winter fishing is at rest on a level patch of snow. The mass of the hut is 80kg. A wind exerts a horizontal force of 205N on the hut, and causes it to accelerate. While in motion, the magnitude of the force of friction acting on the hut is 196N. What is the acceleration of the hut?
is the horizontal force the same thing as net force.pls help
F = m a
205 - 196 = 80 a
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Yes, the horizontal force is the same thing as the net force in this case. The net force is the overall force acting on an object, taking into account all the individual forces acting on it. In this scenario, the wind force and the force of friction are the two forces acting on the ice hut, and the net force is the difference between them.
Yes, the horizontal force mentioned in the question is essentially the net force acting on the hut. The net force is the vector sum of all the forces acting on an object in a specific direction. In this case, the horizontal force is the net force because it is the only force acting on the hut in the horizontal direction.
To find the acceleration of the hut, you can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
The formula for Newton's second law is:
F_net = m * a
where:
F_net is the net force,
m is the mass of the object, and
a is the acceleration.
In this case, you are given the mass of the hut as 80kg and the horizontal force as 205N. The magnitude of the force of friction is also given as 196N.
To find the acceleration, you need to calculate the net force acting on the hut. Since the force of friction acts in the opposite direction to the applied force, it will subtract from the applied force.
So, you can calculate the net force as:
F_net = applied force - force of friction
F_net = 205N - 196N
F_net = 9N
Now that you have the net force and the mass of the hut, you can find the acceleration using Newton's second law:
9N = 80kg * a
To solve for a, divide both sides of the equation by the mass of the hut (80kg):
a = 9N / 80kg
a ≈ 0.1125 m/s²
Therefore, the acceleration of the hut is approximately 0.1125 m/s².