a saturated solution of barium chloride at 30c contains 150g water. how much aditional barium chloride can be dissloved by heating this solution to 50c?
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To determine how much additional barium chloride can be dissolved by heating the solution, we need to calculate the difference in solubility of barium chloride at 30°C and 50°C.
1. Start by finding the solubility of barium chloride at 30°C. The given information states that the solution is saturated, meaning that it contains the maximum amount of solute that can dissolve in the given amount of solvent (water). In this case, the solution contains 150g of water, so the solubility of barium chloride at 30°C is the amount that has already dissolved in the 150g of water.
2. Next, determine the solubility of barium chloride at 50°C. You can do this by looking up the solubility data for barium chloride at different temperatures or using a solubility table. Let's assume that at 50°C, the solubility of barium chloride in water is 200g per 100g of water.
3. Calculate the amount of additional barium chloride that can dissolve by subtracting the amount already dissolved (at 30°C) from the solubility at 50°C.
Let's perform the calculations:
Solubility at 30°C = 150g (given)
Solubility at 50°C = 200g per 100g of water
To convert the solubility at 50°C into the amount of barium chloride dissolved in 150g of water, use a proportion:
(200g / 100g) = (x / 150g)
Cross-multiplying gives:
100g * x = 200g * 150g
100x = 30000g
x = 300g
Therefore, at 50°C, 300g of barium chloride can dissolve in 150g of water.
To determine the additional amount that can be dissolved by heating the solution from 30°C to 50°C, subtract the amount already dissolved in 150g of water at 30°C from the amount that can dissolve in 150g of water at 50°C.
Additional amount dissolved = Solubility at 50°C - Solubility at 30°C
Additional amount dissolved = 300g - 150g
Additional amount dissolved = 150g
So, by heating the solution from 30°C to 50°C, an additional 150g of barium chloride can be dissolved in the 150g of water.