calculate the number of moles of potassium iodate (KIO) that were present in the 5.00mL aliquot of standar potassium iodate solution
Can someone please show me the workings to do questions like this one? thanks =]
Answered above.
To calculate the number of moles of potassium iodate (KIO) present in a given volume of a standard potassium iodate solution, you need to know the concentration of the solution and use the formula:
moles = concentration (in moles per liter) × volume (in liters)
In this case, you are given the volume of the aliquot (5.00 mL) and you need to determine the number of moles of KIO present in that volume.
Step 1: Convert the volume from milliliters (mL) to liters (L):
Since there are 1000 mL in a liter, divide the given volume by 1000:
Volume in liters = 5.00 mL ÷ 1000 = 0.005 L
Step 2: Determine the concentration of the standard potassium iodate solution:
This information needs to be provided in the question or given in the experimental data. It would be expressed in moles per liter (mol/L) or Molarity (M). Let's assume the concentration of the solution is given as 0.25 M.
Step 3: Calculate the number of moles:
moles = concentration × volume
moles = 0.25 M × 0.005 L = 0.00125 moles
Therefore, the number of moles of KIO present in the 5.00 mL aliquot of the standard potassium iodate solution is 0.00125 moles.