algebra

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The sum of the digits of a two-digit number is eleven. If the digits are reversed, the new number is sixty-three less than the original number. Find the original number.


Help? &explain how you got the answer please.

  • algebra -

    let the unit digit be x, and the tens digit be y
    then the origianl number is 10y+x

    and the number reversed would be 10x + y

    10x + y = 10y+x - 63
    9x - 9y = -63
    x - y = -7
    but we also know x+y = 11
    add them
    2x = 4
    x = 2 , then y = 9

    the original number was 92

    check
    old number = 92
    new number = 29
    is 29 less than 92 by 63 ? YES!!!

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