can someone explain how to do this?

The muzzle velocity of 60g bullet leaving 4kg rifle is 500 m/s towards the east. What is recoil velocity of the rifle?

momentumEast=-momentumwest

60g*500m/s= -4000g*V
solve for V

thank you !!:)

Sure! To find the recoil velocity of the rifle, we can use the principle of conservation of momentum. According to this principle, the total momentum before an event is equal to the total momentum after the event, provided there are no external forces acting on the system.

In this case, the bullet and the rifle are considered as a closed system. Initially, the bullet is at rest in the rifle, so its momentum is zero. Therefore, the total momentum before the bullet is fired is zero.

After firing the bullet, it acquires a muzzle velocity of 500 m/s towards the east. The momentum of the bullet is given by the product of its mass and velocity:

Momentum of bullet = mass of bullet × velocity of bullet

Given that the mass of the bullet is 60 g (which is equivalent to 0.06 kg) and the velocity of the bullet is 500 m/s, we can calculate the momentum of the bullet:

Momentum of bullet = 0.06 kg × 500 m/s = 30 kg⋅m/s

According to the conservation of momentum, the total momentum after the bullet is fired should also be zero. Since the only two objects involved are the bullet and the rifle, the rifle must have an equal and opposite momentum to cancel out the momentum of the bullet.

Therefore, the recoil velocity of the rifle can be found by dividing the momentum of the bullet by the mass of the rifle:

Recoil velocity of the rifle = Momentum of bullet / Mass of rifle

Given that the mass of the rifle is 4 kg, we can substitute the values into the equation:

Recoil velocity of the rifle = 30 kg⋅m/s / 4 kg = 7.5 m/s towards the east

So, the recoil velocity of the rifle is 7.5 m/s towards the east.