Trigonometry
posted by Zady
How do you solve these equations algebraically?
y=x^2+4x
2xy=1
y=x^2+2x+3
x+y=1

bobpursley
I would use substitution. For instance, the first:
y= x^2+4x
2x (x^2+4x)=1
x^22x+1=0
(x1)(x1)=0
x=1 y=5
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