lucy makes and sells photo albums her monthly expenses are 600$ plus 2$ for each album she sells. her income for each album sold is 10$ the inequality belowcan be used to find the least number of albums lucy should see so that her income is greater than her expenses
To find the least number of albums Lucy should sell so that her income is greater than her expenses, we need to set up an inequality.
Let's denote the number of albums Lucy sells as 'x'.
According to the given information, her monthly expenses are $600 plus $2 for each album sold. So her expenses equation is:
Expenses = $600 + $2x
Her income for each album sold is $10. Therefore, her income equation is simply:
Income = $10x
Now, to find the least number of albums Lucy should sell, we set up the inequality:
Income > Expenses
$10x > $600 + $2x
To solve this inequality, we need to isolate the variable 'x' on one side of the inequality:
$10x - $2x > $600
Simplifying, we have:
$8x > $600
To solve for 'x', we divide both sides of the inequality by $8:
x > $600 / $8
The final inequality is:
x > 75
This means Lucy should sell more than 75 albums to ensure her income exceeds her expenses.