HI(aq) + KOH(aq)>> H2O(l) + KI(aq)
Express your answer as a chemical equation. Identify all of the phases in your answer.
And what is your question?
The chemical equation for the given reaction is:
HI(aq) + KOH(aq) → H2O(l) + KI(aq)
In this equation, (aq) represents an aqueous solution, and (l) represents a liquid phase.
To write this equation, you need to know the reactants and products for the reaction. The reactants are HI(aq) and KOH(aq), and the products are H2O(l) and KI(aq). The arrow (→) indicates the direction of the reaction, from reactants to products.
To balance the equation, you need to ensure that the number of atoms of each element is the same on both sides of the equation. In this case, let's start by balancing the hydrogen atoms. There is 1 hydrogen atom on the left side (in HI(aq)), and 2 hydrogen atoms on the right side (in H2O(l)). To balance hydrogen, we can add a coefficient of 2 in front of HI(aq). Now the equation becomes:
2 HI(aq) + KOH(aq) → H2O(l) + KI(aq)
Next, let's balance the iodine (I) atoms. There is 1 iodine atom on both sides, so iodine is already balanced.
Finally, let's balance the potassium (K) and oxygen (O) atoms. There is 1 potassium atom on the left side (in KOH(aq)) and 1 potassium atom on the right side (in KI(aq)). There is 1 oxygen atom on the left side (in KOH(aq)) and 1 oxygen atom on the right side (in H2O(l)). Therefore, potassium and oxygen are already balanced.
The final balanced equation with phases is:
2 HI(aq) + KOH(aq) → H2O(l) + KI(aq)