how many moles of aluminum oxide can be produce from 12.8 moles of oxigen gas reacting with execess aluminum
See this example.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the number of moles of aluminum oxide that can be produced from a given amount of oxygen gas, we need to first determine the balanced chemical equation for the reaction between aluminum and oxygen.
The balanced chemical equation for the reaction between aluminum and oxygen to form aluminum oxide is:
4 Al + 3 O2 → 2 Al2O3
From the equation, we can see that for every 3 moles of oxygen gas (O2), we can produce 2 moles of aluminum oxide (Al2O3).
In this case, we have 12.8 moles of oxygen gas. To calculate how many moles of aluminum oxide can be produced, we can set up a simple ratio:
(12.8 moles O2) * (2 moles Al2O3 / 3 moles O2)
By multiplying and dividing appropriately, the moles of oxygen gas cancel out, leaving us with:
(12.8 * 2) / 3 = 8.53 moles of aluminum oxide.
Therefore, 12.8 moles of oxygen gas can produce 8.53 moles of aluminum oxide when reacting with excess aluminum.