algebra
posted by Linda .
Solve using the substitution method. Show your work. If the system has no solution or an infinite number of solutions, state this.
3x – 15y = 12
3x + 24y = 12

Rather than substitution, why don't we just subtract them as they stand.
29y = 0
y = 0
then 3x = 12
x = 4
If you really have to use substitution,
form the first , 3x = 15y  12
into the 2nd
15y  12 + 24y = 12
29y = 0
then 3x = 15(0)  12
3x = 12
x = 4
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